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Found 3 records.

Status: Verified (3)

RFC5831, "GOST R 34.11-94: Hash Function Algorithm", March 2010

Source of RFC: INDEPENDENT

Errata ID: 2303

Status: Verified
Type: Editorial

Reported By: Vasily Dolmatov
Date Reported: 2010-06-17
Verifier Name: Nevil Brownlee
Date Verified: 2013-03-16

Section 9 says:

[GOST3411]  "Information technology.  Cryptographic Data Security.
               Hashing function.", GOST R 34.10-94, Gosudarstvennyi
               Standard of Russian Federation, Government Committee of
               the Russia for Standards, 1994. (In Russian)

It should say:

[GOST3411]  "Information technology.  Cryptographic Data Security.
               Hashing function.", GOST R 34.11-94, Gosudarstvennyi
               Standard of Russian Federation, Government Committee of
               the Russia for Standards, 1994. (In Russian)


Errata ID: 2863

Status: Verified
Type: Editorial

Reported By: Tino Kaufmann
Date Reported: 2011-07-15
Verifier Name: Nevil Brownlee
Date Verified: 2013-03-20

Section 7.3.1 says:

K[1] = 
733D2C20 65686573 74746769 326c6568
626E7373 20657369 79676120 33206D54

It should say:

K[1] = 
733D2C20 65686573 74746769 79676120
626E7373 20657369 326c6568 33206D54



Notes:

The entries 326c6568 and 79676120 have to been swapped


Errata ID: 4262

Status: Verified
Type: Editorial

Reported By: Andrey Pilsky
Date Reported: 2015-02-05
Verifier Name: Nevil Brownlee
Date Verified: 2015-02-17

Section 7.3.2. says:

STEP 3.

   H    = 95BEA0BE 88D5AA02 FE3C9D45 436CE821
          B8287CB6 2CBC135B 3E339EFE F6576CA9

   L    = 00000000 00000000 00000000 00000000
          00000000 00000000 00000000 00000190

   K[1] = 95FEB83E BE3C2833 A09D7C9E BE45B6FE
          88432CF6 D56CBC57 AAE8136D 02215B39

   K[2] = 8695FEB8 1BBE3C28 E2A09D7C 48BE45B6
          DA88432C EBD56CBC 7FABE813 F292215B

   K[2] = 8695FEB8 1BBE3C28 E2A09D7C 48BE45B6
          DA88432C EBD56CBC 7FABE813 F292215B

   K[3] = B9799501 141B413C 1EE2A062 0CB74145
          6FDA88BC D0142A6C FA80AA16 15F2FDB1

It should say:

STEP 3.

   H    = 95BEA0BE 88D5AA02 FE3C9D45 436CE821
          B8287CB6 2CBC135B 3E339EFE F6576CA9

   L    = 00000000 00000000 00000000 00000000
          00000000 00000000 00000000 00000190

   K[1] = 95FEB83E BE3C2833 A09D7C9E BE45B6FE
          88432CF6 D56CBC57 AAE8136D 02215B39
   
   K[2] = 8695FEB8 1BBE3C28 E2A09D7C 48BE45B6
          DA88432C EBD56CBC 7FABE813 F292215B

   K[3] = B9799501 141B413C 1EE2A062 0CB74145
          6FDA88BC D0142A6C FA80AA16 15F2FDB1

Notes:

You need to remove the double K[2]


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